What is the integral of 1/((cos(x))^2) ?

The integral of 1/((cos(x))^2) is tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((cos(x))^2)

\int \frac{1}{( cos ( x ) ) ^{2}} d x

tan (x) + C

Solution steps

\int \frac{1}{( cos ( x ) ) ^{2}} d x

Rewrite using trig identities

= \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= tan (x)

Add a constant to the solution

= tan (x) + C

\frac{\partial}{\partial x} (3 x sin (4 x^{2} y))

y = 3 (x + 1), y = 4 (x + 1), x = 3

\int_{0}^{\frac{3 π}{2}} 2 ∣ sin (x) ∣ d x

\int e^{\frac{y}{3}} d y

\frac{x ^{2} - 4 x + 2}{x + 3}

What is the integral of 1/((cos(x))^2) ?
The integral of 1/((cos(x))^2) is tan(x)+C