What is the tangent of y= 2/(sqrt(x)),(1/16 ,8) ?

The tangent of y= 2/(sqrt(x)),(1/16 ,8) is y=-64x+12

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tangent of y= 2/(sqrt(x)),(1/16 ,8)

tangent of

y = \frac{2}{x}, (\frac{1}{16}, 8)

y = - 64 x + 12

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{1}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{2}{x}

(\frac{1}{16}, 8) : m = - 64

Find the line with slope m=

- 64

and passing through

(\frac{1}{16}, 8) : y = - 64 x + 12

y = - 64 x + 12

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What is the tangent of y= 2/(sqrt(x)),(1/16 ,8) ?
The tangent of y= 2/(sqrt(x)),(1/16 ,8) is y=-64x+12