What is area 1/((sqrt(1-7x))),-6<x<0 ?

The answer to area 1/((sqrt(1-7x))),-6<x<0 is (2sqrt(43)-2)/7

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area 1/((sqrt(1-7x))),-6<x<0

area

\frac{1}{( 1 - 7 x )}, - 6 < x < 0

\frac{2 43 - 2}{7}

Decimal Notation

1.58783 \dots

Solution steps

Apply the area formula:

\int_{- 6}^{0} \frac{1}{1 - 7 x} d x

Solve

\int_{- 6}^{0} \frac{1}{1 - 7 x} d x : \frac{2 43 - 2}{7}

The area is:

= \frac{2 43 - 2}{7}

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\int \frac{1}{64 + x ^{2}} d x

What is area 1/((sqrt(1-7x))),-6<x<0 ?
The answer to area 1/((sqrt(1-7x))),-6<x<0 is (2sqrt(43)-2)/7