What is the derivative of 8e^{-7x} ?

The derivative of 8e^{-7x} is -56e^{-7x}

What is the first derivative of 8e^{-7x} ?

The first derivative of 8e^{-7x} is -56e^{-7x}

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derivative of

8 e^{- 7 x}

- 56 e^{- 7 x}

Solution steps

\frac{d}{d x} (8 e^{- 7 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (e^{- 7 x})

Apply the chain rule:

e^{- 7 x} \frac{d}{d x} (- 7 x)

= e^{- 7 x} \frac{d}{d x} (- 7 x)

\frac{d}{d x} (- 7 x) = - 7

= 8 e^{- 7 x} (- 7)

Simplify

= - 56 e^{- 7 x}

\int 3 sin^{3} (3 x co) s^{3} 3 x d x

y^{^{'}} = x^{3}

\int_{7}^{9} (x^{2} + 2 x - 8) d x

\frac{\partial}{\partial x} (sin (8 θ))

\int_{1}^{\infty} e^{- 9 x} d x

What is the derivative of 8e^{-7x} ?
The derivative of 8e^{-7x} is -56e^{-7x}
What is the first derivative of 8e^{-7x} ?
The first derivative of 8e^{-7x} is -56e^{-7x}