What is the solution for (dy)/(dx)=(xy)^2,y(0)=1 ?

The solution for (dy)/(dx)=(xy)^2,y(0)=1 is y=-3/(x^3-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(xy)^2,y(0)=1

\frac{d y}{d x} = (x y)^{2}, y (0) = 1

y = - \frac{3}{x ^{3} - 3}

Solution steps

\frac{d y}{d x} = (x y)^{2}

Solve separable ODE:

y = - \frac{3}{x ^{3} - 3}

y = - \frac{3}{x ^{3} - 3}

\int \frac{x ^{5}}{x ^{6} + 2} d x

x \to 9 lim (\frac{1}{( x - 9 ) ^{3}})

7 cos (7 x), 7 - 7 cos (7 x)

\int sec^{9} (x) tan (x) d x

\frac{d}{d x} (sin (π \cdot x))

What is the solution for (dy)/(dx)=(xy)^2,y(0)=1 ?
The solution for (dy)/(dx)=(xy)^2,y(0)=1 is y=-3/(x^3-3)