What is the slope of y=(x^2)/3+x+1/2 ?

The slope of y=(x^2)/3+x+1/2 is (2x)/3+1

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slope of y=(x^2)/3+x+1/2

slope

y = \frac{x ^{2}}{3} + x + \frac{1}{2}

\frac{2 x}{3} + 1

Solution steps

y = \frac{x ^{2}}{3} + x + \frac{1}{2}

In order to find the slope of the function, take the derivative of

\frac{x ^{2}}{3} + x + \frac{1}{2}

\frac{d}{d x} (\frac{x ^{2}}{3} + x + \frac{1}{2}) = \frac{2 x}{3} + 1

\frac{2 x}{3} + 1

\frac{90}{x}

\int_{0}^{2} \frac{x}{( 1 + x ^{2} ) ^{2}} d x

\frac{d}{d x} ((5 - 6 x)^{5})

2 x + \frac{3}{x}

x \to \infty lim (x e^{- 1})