What is the derivative of 4x^{-3} ?

The derivative of 4x^{-3} is -(12)/(x^4)

What is the first derivative of 4x^{-3} ?

The first derivative of 4x^{-3} is -(12)/(x^4)

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derivative of

4 x^{- 3}

- \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (4 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 3 x^{- 3 - 1})

Simplify

4 (- 3 x^{- 3 - 1}) : - \frac{12}{x ^{4}}

= - \frac{12}{x ^{4}}

x \to - 5 lim (∣ x ∣ - 5)

(1 - x)^{- 100}

e^{- 0.4 t} cos (12 t)

\int \frac{2 x}{x ^{2} + 4} d x

T \to \infty lim (f (T))

What is the derivative of 4x^{-3} ?
The derivative of 4x^{-3} is -(12)/(x^4)
What is the first derivative of 4x^{-3} ?
The first derivative of 4x^{-3} is -(12)/(x^4)