What is the tangent of f(x)=3x^2+2x,\at x=3 ?

The tangent of f(x)=3x^2+2x,\at x=3 is y=20x-27

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tangent of f(x)=3x^2+2x,\at x=3

tangent of

f (x) = 3 x^{2} + 2 x, at x = 3

y = 20 x - 27

Solution steps

Find the tangent point:

(3, 33)

Find the slope of

f (x) = 3 x^{2} + 2 x : \frac{df ( x )}{d x} = 6 x + 2

Compute the slope of

f (x) = 3 x^{2} + 2 x

x = 3 : m = 20

Find the line with slope m=

20

and passing through

(3, 33) : y = 20 x - 27

y = 20 x - 27

\int \frac{sin ( x )}{cos ^{3} ( x )} d x

\frac{d}{d x} (x - \frac{1}{2} x^{2})

\frac{d y}{d x} = sin (7 e^{x})

\int sec^{2} (θ) tan^{9} (θ) d θ

x \to 4 lim (4)

What is the tangent of f(x)=3x^2+2x,\at x=3 ?
The tangent of f(x)=3x^2+2x,\at x=3 is y=20x-27