What is the derivative of (2x^3+3x-1^4) ?

The derivative of (2x^3+3x-1^4) is 4(2x^3+3x-1)^3(6x^2+3)

What is the first derivative of (2x^3+3x-1^4) ?

The first derivative of (2x^3+3x-1^4) is 4(2x^3+3x-1)^3(6x^2+3)

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\frac{d}{d x} ((2 x^{3} + 3 x - 1)^{4})

4 (2 x^{3} + 3 x - 1)^{3} (6 x^{2} + 3)

Solution steps

\frac{d}{d x} ((2 x^{3} + 3 x - 1)^{4})

Apply the chain rule:

4 (2 x^{3} + 3 x - 1)^{3} \frac{d}{d x} (2 x^{3} + 3 x - 1)

= 4 (2 x^{3} + 3 x - 1)^{3} \frac{d}{d x} (2 x^{3} + 3 x - 1)

\frac{d}{d x} (2 x^{3} + 3 x - 1) = 6 x^{2} + 3

= 4 (2 x^{3} + 3 x - 1)^{3} (6 x^{2} + 3)

\frac{\partial}{\partial x} (3 x^{3} y^{3} - 2 x^{2} + 3 y + 40)

2 - \frac{4}{t}

\int \frac{ln ( 13 x )}{x} d x

e^{3 x}

x \to \infty lim (\frac{e ^{2 x}}{5 ^{2 x}})

What is the derivative of (2x^3+3x-1^4) ?
The derivative of (2x^3+3x-1^4) is 4(2x^3+3x-1)^3(6x^2+3)
What is the first derivative of (2x^3+3x-1^4) ?
The first derivative of (2x^3+3x-1^4) is 4(2x^3+3x-1)^3(6x^2+3)