What is the derivative of (x^2+1^4) ?

The derivative of (x^2+1^4) is 8x(x^2+1)^3

What is the first derivative of (x^2+1^4) ?

The first derivative of (x^2+1^4) is 8x(x^2+1)^3

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\frac{d}{d x} ((x^{2} + 1)^{4})

8 x (x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{4})

Apply the chain rule:

4 (x^{2} + 1)^{3} \frac{d}{d x} (x^{2} + 1)

= 4 (x^{2} + 1)^{3} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 4 (x^{2} + 1)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} + 1)^{3}

\int_{1}^{7} x^{3} d x

25 - x^{2}

\int \frac{1}{x ^{2} + 25} d x

\int \frac{x}{x ^{2} - 8} d x

q^{^{''}} + 2 q^{^{'}} + 4 q = 50 cos (t)

What is the derivative of (x^2+1^4) ?
The derivative of (x^2+1^4) is 8x(x^2+1)^3
What is the first derivative of (x^2+1^4) ?
The first derivative of (x^2+1^4) is 8x(x^2+1)^3