What is the integral of 1/(sqrt(x+4)) ?

The integral of 1/(sqrt(x+4)) is 2sqrt(x+4)+C

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integral of 1/(sqrt(x+4))

\int \frac{1}{x + 4} d x

2 x + 4 + C

Solution steps

\int \frac{1}{x + 4} d x

Apply u-substitution

: \int 2 d u

= \int 2 d u

Integral of a constant:

\int a d x = a x

= 2 u

Substitute back

u = x + 4

= 2 x + 4

Add a constant to the solution

= 2 x + 4 + C

f (x) = x - a

\frac{d}{d x} (x ln (x) - x)

\frac{\partial}{\partial y} (x cos (y - x))

\int \frac{3 x ^{2}}{x ^{3} + 7} d x

\frac{d}{d x} (x y)

What is the integral of 1/(sqrt(x+4)) ?
The integral of 1/(sqrt(x+4)) is 2sqrt(x+4)+C