What is the (sqrt(t))^' ?

The (sqrt(t))^' is 1/(2sqrt(t))

What is the first (sqrt(t))^' ?

The first (sqrt(t))^' is 1/(2sqrt(t))

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(t)^{^{'}}

\frac{1}{2 t}

Solution steps

(t)^{'}

Apply radical rule:

a = a^{\frac{1}{2}}

= (t^{\frac{1}{2}})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} t^{\frac{1}{2} - 1}

Simplify

\frac{1}{2} t^{\frac{1}{2} - 1} : \frac{1}{2 t}

= \frac{1}{2 t}

n = 1 \sum \infty \frac{n + 4}{n ^{2}}

y^{^{''}} + 16 y = 0

\frac{\partial}{\partial x} ((x^{\frac{1}{2}} + y^{\frac{1}{2}})^{2})

\int 5 + \frac{3 x ^{2}}{2 x ^{3} + 7} d x