What is the derivative of f(x)=sqrt(7x+8) ?

The derivative of f(x)=sqrt(7x+8) is 7/(2sqrt(7x+8))

What is the first derivative of f(x)=sqrt(7x+8) ?

The first derivative of f(x)=sqrt(7x+8) is 7/(2sqrt(7x+8))

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derivative of

f (x) = 7 x + 8

\frac{7}{2 7 x + 8}

Solution steps

\frac{d}{d x} (7 x + 8)

Apply the chain rule:

\frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

= \frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

\frac{d}{d x} (7 x + 8) = 7

= \frac{1}{2 7 x + 8} \cdot 7

Simplify

\frac{1}{2 7 x + 8} \cdot 7 : \frac{7}{2 7 x + 8}

= \frac{7}{2 7 x + 8}

e^{- 0}

\frac{d}{d x} (x \cdot sin (y))

9 x cos (x^{2})

x \to - \infty lim (6^{x})

y^{^{'}} - 3 y = e^{x}

What is the derivative of f(x)=sqrt(7x+8) ?
The derivative of f(x)=sqrt(7x+8) is 7/(2sqrt(7x+8))
What is the first derivative of f(x)=sqrt(7x+8) ?
The first derivative of f(x)=sqrt(7x+8) is 7/(2sqrt(7x+8))