What is the integral from-1 to 1 of (10)/(x^2) ?

The integral from-1 to 1 of (10)/(x^2) is diverges

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integral from-1 to 1 of (10)/(x^2)

\int_{- 1}^{1} \frac{10}{x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{1} \frac{10}{x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{10}{x ^{2}} d x + \int_{0}^{1} \frac{10}{x ^{2}} d x

\int_{- 1}^{0} \frac{10}{x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{3}^{12} (6 x + 1) d x

\int (\frac{1}{x ^{10}} - x^{10} - \frac{1}{3}) d x

4 t^{3} cos (t)

\int_{- \infty}^{12} r e^{\frac{r}{3}} d r

\frac{\partial}{\partial t} (x y z^{2} tan (y t))

What is the integral from-1 to 1 of (10)/(x^2) ?
The integral from-1 to 1 of (10)/(x^2) is diverges