What is the tangent of x^2+xy-y^2=-9,(3,6) ?

The tangent of x^2+xy-y^2=-9,(3,6) is y= 4/3 x+2

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tangent of x^2+xy-y^2=-9,(3,6)

tangent of

x^{2} + x y - y^{2} = - 9, (3, 6)

y = \frac{4}{3} x + 2

Solution steps

Find the slope of

x^{2} + x y - y^{2} = - 9 : \frac{d y}{d x} = \frac{- 2 x - y}{x - 2 y}

Compute the slope of

x^{2} + x y - y^{2} = - 9

(3, 6) : m = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(3, 6) : y = \frac{4}{3} x + 2

y = \frac{4}{3} x + 2

\frac{2 x}{1 + x ^{2}}

F (x) = ln (2 x), y = 0, y = 2

5 sin (x), 5 cos (2 x), 0, \frac{π}{2}

\int_{- 3}^{3} \frac{1}{2} (81 - x^{4}) d x

\frac{d}{d x} (25 x^{2} - 1)

What is the tangent of x^2+xy-y^2=-9,(3,6) ?
The tangent of x^2+xy-y^2=-9,(3,6) is y= 4/3 x+2