What is the limit as x approaches 3 of ((x^2-9))/(2x-6) ?

The limit as x approaches 3 of ((x^2-9))/(2x-6) is 3

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limit as x approaches 3 of ((x^2-9))/(2x-6)

x \to 3 lim (\frac{( x ^{2} - 9 )}{2 x - 6})

3

Solution steps

x \to 3 lim (\frac{x ^{2} - 9}{2 x - 6})

Simplify

\frac{x ^{2} - 9}{2 x - 6} : \frac{1}{2} (x + 3)

= x \to 3 lim (\frac{1}{2} (x + 3))

Plug in the value

x = 3

= \frac{1}{2} (3 + 3)

Simplify

\frac{1}{2} (3 + 3) : 3

= 3

x \to \infty lim (\frac{2 ^{x}}{3 ^{x - 1}})

\int 2 - x d x

\frac{d}{d x} (cos (\frac{π}{2} x))

\int_{- π}^{0} x d x

\int 2 e^{x^{2}} d x

What is the limit as x approaches 3 of ((x^2-9))/(2x-6) ?
The limit as x approaches 3 of ((x^2-9))/(2x-6) is 3