What is (\partial)/(\partial y)(3x+4y) ?

The answer to (\partial)/(\partial y)(3x+4y) is 4

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(\partial)/(\partial y)(3x+4y)

\frac{\partial}{\partial y} (3 x + 4 y)

4

Solution steps

\frac{\partial}{\partial y} (3 x + 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x) + \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 + 4

Simplify

= 4

x \to 0 lim (a^{x} + a^{- x})

\int (3 x + 4)^{6} d x

y^{^{'}} + e^{x} y = 19 e^{x}

\frac{\partial}{\partial w} ((y - w (x + x^{2}))^{2})

What is (\partial)/(\partial y)(3x+4y) ?
The answer to (\partial)/(\partial y)(3x+4y) is 4