What is the derivative of 7(x^3-x)^4 ?

The derivative of 7(x^3-x)^4 is 28(x^3-x)^3(3x^2-1)

What is the first derivative of 7(x^3-x)^4 ?

The first derivative of 7(x^3-x)^4 is 28(x^3-x)^3(3x^2-1)

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derivative of

7 (x^{3} - x)^{4}

28 (x^{3} - x)^{3} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (7 (x^{3} - x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} ((x^{3} - x)^{4})

Apply the chain rule:

4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

= 4 (x^{3} - x)^{3} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= 7 \cdot 4 (x^{3} - x)^{3} (3 x^{2} - 1)

Simplify

= 28 (x^{3} - x)^{3} (3 x^{2} - 1)

\frac{d}{d x} (\frac{3 x - 8}{x ^{2} - 1})

y^{^{'}} + \frac{3 y}{x} = \frac{3}{x}

y = \frac{9}{x ^{- 6}}

{\frac{s}{( s - 2 ) ( s - 3 ) ( s - 6 )}}

\frac{d}{d x} ((x + a) e^{3 x} + b)

What is the derivative of 7(x^3-x)^4 ?
The derivative of 7(x^3-x)^4 is 28(x^3-x)^3(3x^2-1)
What is the first derivative of 7(x^3-x)^4 ?
The first derivative of 7(x^3-x)^4 is 28(x^3-x)^3(3x^2-1)