What is the solution for (dy)/(dt)=6y+2t-4,y(0)=3 ?

The solution for (dy)/(dt)=6y+2t-4,y(0)=3 is y=-t/3+11/18+43/18 e^{6t}

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(dy)/(dt)=6y+2t-4,y(0)=3

\frac{d y}{d t} = 6 y + 2 t - 4, y (0) = 3

y = - \frac{t}{3} + \frac{11}{18} + \frac{43}{18} e^{6 t}

Solution steps

\frac{d y}{d t} = 6 y + 2 t - 4

Solve linear ODE:

y = - \frac{t}{3} + \frac{11}{18} + \frac{43}{18} e^{6 t}

y = - \frac{t}{3} + \frac{11}{18} + \frac{43}{18} e^{6 t}

x \to 4 lim (\frac{x ^{2}}{x - 4})

\int 12 x ln (2 x) d x

\frac{d}{d x} (e^{x \cdot y})

f (x) = sin (tan (1 + x^{3}))

x \to 3 lim (\frac{x}{2})

What is the solution for (dy)/(dt)=6y+2t-4,y(0)=3 ?
The solution for (dy)/(dt)=6y+2t-4,y(0)=3 is y=-t/3+11/18+43/18 e^{6t}