What is the derivative of 14-1/2 x^{-3} ?

The derivative of 14-1/2 x^{-3} is 3/(2x^4)

What is the first derivative of 14-1/2 x^{-3} ?

The first derivative of 14-1/2 x^{-3} is 3/(2x^4)

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\frac{d}{d x} (14 - \frac{1}{2} x^{- 3})

\frac{3}{2 x ^{4}}

Solution steps

\frac{d}{d x} (14 - \frac{1}{2} x^{- 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (14) - \frac{d}{d x} (\frac{1}{2} x^{- 3})

\frac{d}{d x} (14) = 0

\frac{d}{d x} (\frac{1}{2} x^{- 3}) = - \frac{3}{2 x ^{4}}

= 0 - (- \frac{3}{2 x ^{4}})

Simplify

= \frac{3}{2 x ^{4}}

y = arcsin (8 x + 1)

\frac{d}{d x} (cos^{2} (2 x^{4} - 4))

\int \frac{sec ^{4} ( x )}{tan ^{3} ( x )} d x

\int (x - 5) cos (x) d x

x \to 2 lim (\frac{( x - 2 )}{x - 2})

What is the derivative of 14-1/2 x^{-3} ?
The derivative of 14-1/2 x^{-3} is 3/(2x^4)
What is the first derivative of 14-1/2 x^{-3} ?
The first derivative of 14-1/2 x^{-3} is 3/(2x^4)