What is the derivative of (40/(x+1)) ?

The derivative of (40/(x+1)) is -(40)/((x+1)^2)

What is the first derivative of (40/(x+1)) ?

The first derivative of (40/(x+1)) is -(40)/((x+1)^2)

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\frac{d}{d x} (\frac{40}{x + 1})

- \frac{40}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{40}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 40 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 40 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 40 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

40 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : - \frac{40}{( x + 1 ) ^{2}}

= - \frac{40}{( x + 1 ) ^{2}}

\frac{( s + 2 )}{s ^{2} + 4}

\int 1 tan^{2} (x) d x

g (x) = 14 (1. 7^{x})

\frac{\partial}{\partial y} (e^{3 x})

x \to 2 - lim (\frac{x}{∣ x ∣})

What is the derivative of (40/(x+1)) ?
The derivative of (40/(x+1)) is -(40)/((x+1)^2)
What is the first derivative of (40/(x+1)) ?
The first derivative of (40/(x+1)) is -(40)/((x+1)^2)