What is the integral of (3x^2-8x+2) ?

The integral of (3x^2-8x+2) is x^3-4x^2+2x+C

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integral of (3x^2-8x+2)

\int (3 x^{2} - 8 x + 2) d x

x^{3} - 4 x^{2} + 2 x + C

Solution steps

\int 3 x^{2} - 8 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 8 x d x + \int 2 d x

\int 3 x^{2} d x = x^{3}

\int 8 x d x = 4 x^{2}

\int 2 d x = 2 x

= x^{3} - 4 x^{2} + 2 x

Add a constant to the solution

= x^{3} - 4 x^{2} + 2 x + C

\frac{3}{cos ^{2} ( 3 x + 5 )}

\frac{d}{d t} ((t + 3)^{\frac{2}{3}} (2 t^{2} - 3)^{3})

f (t) = 5 t - 9 t^{2}

\frac{\partial}{\partial x} (x^{2} - x y + y^{2} + 3 x - 2 y + 1)

y^{2} = 2 x y y^{^{'}}

What is the integral of (3x^2-8x+2) ?
The integral of (3x^2-8x+2) is x^3-4x^2+2x+C