What is the solution for y^'+3/x y= 1/(x^2) ?

The solution for y^'+3/x y= 1/(x^2) is y= 1/(2x)+(c_{1})/(x^3)

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y^'+3/x y= 1/(x^2)

y^{^{'}} + \frac{3}{x} y = \frac{1}{x ^{2}}

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

Solution steps

y^{'} (x) + \frac{3}{x} y = \frac{1}{x ^{2}}

Solve linear ODE:

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

y = \frac{1}{2 x} + \frac{c _{1}}{x ^{3}}

\frac{d}{d x} (4 - 3 sin (3 x))

y^{^{''}} + 9 y = - sin (3 x), y (0) = 0, y^{^{'}} (0) = \frac{1}{6}

x^{3}, 0

1.1 e^{0.78 t}

\frac{d}{d x} (x^{3} (x - 9)^{2})

What is the solution for y^'+3/x y= 1/(x^2) ?
The solution for y^'+3/x y= 1/(x^2) is y= 1/(2x)+(c_{1})/(x^3)