What is the solution for (dy)/(dx)+5x^4y=x^4 ?

The solution for (dy)/(dx)+5x^4y=x^4 is y=(e^{-x^5+c_{1}})/5+1/5

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(dy)/(dx)+5x^4y=x^4

\frac{d y}{d x} + 5 x^{4} y = x^{4}

y = \frac{e ^{- x^{5} + c_{1}}}{5} + \frac{1}{5}

Solution steps

\frac{d y}{d x} + 5 x^{4} y = x^{4}

Solve separable ODE:

y = \frac{e ^{- x^{5} + c_{1}}}{5} + \frac{1}{5}

y = \frac{e ^{- x^{5} + c_{1}}}{5} + \frac{1}{5}

\frac{d}{d x} (2 e^{x} cos (2 x))

y = 1.45 e^{59.9 t} sin (201 t)

\int_{2}^{6} t^{4} ln (3 t) d t

f (x) = x^{2} - 16

y = \frac{3}{x} + 2 x^{3}, 2 \leq x \leq 3

What is the solution for (dy)/(dx)+5x^4y=x^4 ?
The solution for (dy)/(dx)+5x^4y=x^4 is y=(e^{-x^5+c_{1}})/5+1/5