What is the derivative of g(x)=(x^2+3)(x^2-4x) ?

The derivative of g(x)=(x^2+3)(x^2-4x) is 4x^3-12x^2+6x-12

What is the first derivative of g(x)=(x^2+3)(x^2-4x) ?

The first derivative of g(x)=(x^2+3)(x^2-4x) is 4x^3-12x^2+6x-12

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derivative of

g (x) = (x^{2} + 3) (x^{2} - 4 x)

4 x^{3} - 12 x^{2} + 6 x - 12

Solution steps

\frac{d}{d x} ((x^{2} + 3) (x^{2} - 4 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} + 3, g = x^{2} - 4 x

= \frac{d}{d x} (x^{2} + 3) (x^{2} - 4 x) + \frac{d}{d x} (x^{2} - 4 x) (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

= 2 x (x^{2} - 4 x) + (2 x - 4) (x^{2} + 3)

Simplify

2 x (x^{2} - 4 x) + (2 x - 4) (x^{2} + 3) : 4 x^{3} - 12 x^{2} + 6 x - 12

= 4 x^{3} - 12 x^{2} + 6 x - 12

- \frac{t}{4} - \frac{3}{8} sin (2 t)

\int_{0}^{1} π (x - x^{4}) d x

\int - 3 x^{- 1} d x

f (x) = (x^{3} - 2)

(2 x - 7)^{5}

What is the derivative of g(x)=(x^2+3)(x^2-4x) ?
The derivative of g(x)=(x^2+3)(x^2-4x) is 4x^3-12x^2+6x-12
What is the first derivative of g(x)=(x^2+3)(x^2-4x) ?
The first derivative of g(x)=(x^2+3)(x^2-4x) is 4x^3-12x^2+6x-12