What is the integral from-6 to 1 of-2x^2-10x+12 ?

The integral from-6 to 1 of-2x^2-10x+12 is 343/3

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integral from-6 to 1 of-2x^2-10x+12

\int_{- 6}^{1} - 2 x^{2} - 10 x + 12 d x

\frac{343}{3}

Decimal Notation

114.33333 \dots

Solution steps

\int_{- 6}^{1} - 2 x^{2} - 10 x + 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 6}^{1} 2 x^{2} d x - \int_{- 6}^{1} 10 x d x + \int_{- 6}^{1} 12 d x

\int_{- 6}^{1} 2 x^{2} d x = \frac{434}{3}

\int_{- 6}^{1} 10 x d x = - 175

\int_{- 6}^{1} 12 d x = 84

= - \frac{434}{3} - (- 175) + 84

Simplify

- \frac{434}{3} - (- 175) + 84 : \frac{343}{3}

= \frac{343}{3}

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\frac{d}{d x} (x^{2} arcsinh (9 x))

\int \frac{1}{x ^{5}} - \frac{3}{x ^{2}} d x

What is the integral from-6 to 1 of-2x^2-10x+12 ?
The integral from-6 to 1 of-2x^2-10x+12 is 343/3