What is the derivative of 2x^3-1 ?

The derivative of 2x^3-1 is 6x^2

What is the first derivative of 2x^3-1 ?

The first derivative of 2x^3-1 is 6x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

2 x^{3} - 1

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (1) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

y = (1 + 2 x)^{11}, (0, 1)

\frac{( 2 s - 1 )}{s ^{2} ( s + 1 ) ^{3}}

\int (x^{5} + 8 x^{3} - 9 x^{2} + 7 x - 5) d x

\int (e^{x} + \frac{1}{e ^{x}})^{2} d x

\int_{0}^{1} cos (x^{2}) d x