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Popular >

(8y^2-xy)dx+x^2dy=0

Solution

(8 y^{2} - x y) d x + x^{2} d y = 0

Solution

y = \frac{x}{8 ln ( x ) + c _{1}}

Solution steps

(8 y^{2} - x y) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{8 ln ( x ) + c _{1}}

y = \frac{x}{8 ln ( x ) + c _{1}}

Popular Examples

(e^{x} sin (x))^{^{'}}

integral of 13x^2

\int 13 x^{2} d x

derivative of (x^2-5x+8)(3x^2-2)derivative of

(x^{2} - 5 x + 8) (3 x^{2} - 2)

inverse oflaplace 1/(s^5)inverse laplace

\frac{1}{s ^{5}}

area y=0.7(x+0.2)^3+4,1,-0.1 area

y = 0.7 (x + 0.2)^{3} + 4, 1, - 0.1

Frequently Asked Questions (FAQ)

What is the solution for (8y^2-xy)dx+x^2dy=0 ?
The solution for (8y^2-xy)dx+x^2dy=0 is y= x/(8ln(x)+c_{1)}