What is the integral from 0 to 1 of 3ln(4x) ?

The integral from 0 to 1 of 3ln(4x) is 3(2ln(2)-1)

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integral from 0 to 1 of 3ln(4x)

\int_{0}^{1} 3 ln (4 x) d x

3 (2 ln (2) - 1)

Decimal Notation

1.15888 \dots

Solution steps

\int_{0}^{1} 3 ln (4 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} ln (4 x) d x

Apply Integration By Parts

: [x ln (4 x) - \int 1 d x]_{0}^{1}

= 3 [x ln (4 x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= 3 [x ln (4 x) - x]_{0}^{1}

Compute the boundaries:

2 ln (2) - 1

= 3 (2 ln (2) - 1)

\frac{d y}{d x} = 9 x y

\int x (x - 2) d x

4 \frac{d ^{2} y}{d x ^{2}} - 5 y = 0

x \to 4 lim (\frac{sin ( x )}{x})

\frac{d y}{d x}, y e^{y} \cdot \frac{x - 1}{x + 1} = \frac{x ^{3}}{3} - x

What is the integral from 0 to 1 of 3ln(4x) ?
The integral from 0 to 1 of 3ln(4x) is 3(2ln(2)-1)