What is (\partial)/(\partial y)(y^2cos(x)) ?

The answer to (\partial)/(\partial y)(y^2cos(x)) is 2ycos(x)

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(\partial)/(\partial y)(y^2cos(x))

\frac{\partial}{\partial y} (y^{2} cos (x))

2 y cos (x)

Solution steps

\frac{\partial}{\partial y} (y^{2} cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (x) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= cos (x) \cdot 2 y^{2 - 1}

Simplify

= 2 y cos (x)

\frac{\partial}{\partial x} (6 tan (x y))

n = 1 \sum \infty sin (\frac{1}{2 ^{n}})

2 \cdot cos (5 t)

\frac{\partial}{\partial y} (e^{5 x} sin (5 y))

\int - 4 tan (x) d x

What is (\partial)/(\partial y)(y^2cos(x)) ?
The answer to (\partial)/(\partial y)(y^2cos(x)) is 2ycos(x)