What is the derivative of sin^3(2x+1) ?

The derivative of sin^3(2x+1) is 6sin^2(2x+1)cos(2x+1)

What is the first derivative of sin^3(2x+1) ?

The first derivative of sin^3(2x+1) is 6sin^2(2x+1)cos(2x+1)

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\frac{d}{d x} (sin^{3} (2 x + 1))

6 sin^{2} (2 x + 1) cos (2 x + 1)

Solution steps

\frac{d}{d x} (sin^{3} (2 x + 1))

Apply the chain rule:

3 (sin (2 x + 1))^{2} \frac{d}{d x} (sin (2 x + 1))

= 3 (sin (2 x + 1))^{2} \frac{d}{d x} (sin (2 x + 1))

\frac{d}{d x} (sin (2 x + 1)) = cos (2 x + 1) \cdot 2

= 3 (sin (2 x + 1))^{2} cos (2 x + 1) \cdot 2

Simplify

= 6 sin^{2} (2 x + 1) cos (2 x + 1)

\int_{1}^{3} x^{3} d x

\frac{5}{( s + 4 ) ^{2} ( s + 1 )}

\frac{t}{( t - 1 ) ^{2}}

(1, 1), (- 3, - 3)

y = x^{2} + x - 1.0 E - 13

What is the derivative of sin^3(2x+1) ?
The derivative of sin^3(2x+1) is 6sin^2(2x+1)cos(2x+1)
What is the first derivative of sin^3(2x+1) ?
The first derivative of sin^3(2x+1) is 6sin^2(2x+1)cos(2x+1)