What is the derivative of (((10-x))/4)^2+(x^2)/(4pi) ?

The derivative of (((10-x))/4)^2+(x^2)/(4pi) is -1/8 (10-x)+x/(2pi)

What is the first derivative of (((10-x))/4)^2+(x^2)/(4pi) ?

The first derivative of (((10-x))/4)^2+(x^2)/(4pi) is -1/8 (10-x)+x/(2pi)

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derivative of

(\frac{( 10 - x )}{4})^{2} + \frac{x ^{2}}{4 π}

- \frac{1}{8} (10 - x) + \frac{x}{2 π}

Solution steps

\frac{d}{d x} ((\frac{10 - x}{4})^{2} + \frac{x ^{2}}{4 π})

Simplify

(\frac{10 - x}{4})^{2} + \frac{x ^{2}}{4 π} : \frac{( 10 - x ) ^{2}}{16} + \frac{x ^{2}}{4 π}

= \frac{d}{d x} (\frac{( 10 - x ) ^{2}}{16} + \frac{x ^{2}}{4 π})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{( 10 - x ) ^{2}}{16}) + \frac{d}{d x} (\frac{x ^{2}}{4 π})

\frac{d}{d x} (\frac{( 10 - x ) ^{2}}{16}) = - \frac{1}{8} (10 - x)

\frac{d}{d x} (\frac{x ^{2}}{4 π}) = \frac{x}{2 π}

= - \frac{1}{8} (10 - x) + \frac{x}{2 π}

\int x sin (10 - x) d x

\int_{6}^{7} t sin (π t) d t

\frac{d}{d x} (lo g_{12} (x^{2} + n x))

\frac{d}{d x} (2 sinh (\frac{x}{5}))

x \to 1 lim (\frac{x}{x ^{2} - 1})

What is the derivative of (((10-x))/4)^2+(x^2)/(4pi) ?
The derivative of (((10-x))/4)^2+(x^2)/(4pi) is -1/8 (10-x)+x/(2pi)
What is the first derivative of (((10-x))/4)^2+(x^2)/(4pi) ?
The first derivative of (((10-x))/4)^2+(x^2)/(4pi) is -1/8 (10-x)+x/(2pi)