What is derivative of f(x)=24t^{3/2}+4t^{1/2} ?

The answer to derivative of f(x)=24t^{3/2}+4t^{1/2} is (dt)/(dx)=0

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derivative of f(x)=24t^{3/2}+4t^{1/2}

derivative of

f (x) = 24 t^{\frac{3}{2}} + 4 t^{\frac{1}{2}}

\frac{d t}{d x} = 0

Solution steps

f (x) = 24 t^{\frac{3}{2}} + 4 t^{\frac{1}{2}}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{2 \frac{d t}{d x} + 36 \frac{d t}{d x} t}{t ^{\frac{1}{2}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int 2 - y^{2} d y

\int_{- 2}^{4} (1 + 2 x - 3 x^{2} + x^{3}) d x

\int \frac{1}{y ^{2} + y} d y

\frac{x}{x ^{2} + 49}

\frac{d}{d x} (\frac{e ^{x}}{4 x ^{2} + 9})

What is derivative of f(x)=24t^{3/2}+4t^{1/2} ?
The answer to derivative of f(x)=24t^{3/2}+4t^{1/2} is (dt)/(dx)=0