What is the derivative of y=(4x)/(e^x) ?

The derivative of y=(4x)/(e^x) is (4(1-x))/(e^x)

What is the first derivative of y=(4x)/(e^x) ?

The first derivative of y=(4x)/(e^x) is (4(1-x))/(e^x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{4 x}{e ^{x}}

\frac{4 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{4 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{4 ( 1 - x )}{e ^{x}}

= \frac{4 ( 1 - x )}{e ^{x}}

\int_{- 1}^{x^{3}} t^{5} d t

\int 3 tan^{2} (x) sec^{2} (x) d x

\frac{\partial}{\partial x} (\frac{x y}{4 x + 3 y})

y = sin (x)

\int e^{x} - x^{e} + \frac{5}{x} d x

What is the derivative of y=(4x)/(e^x) ?
The derivative of y=(4x)/(e^x) is (4(1-x))/(e^x)
What is the first derivative of y=(4x)/(e^x) ?
The first derivative of y=(4x)/(e^x) is (4(1-x))/(e^x)