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Popular >

y^'=e^{(y-x)}

Solution

y^{^{'}} = e^{(y - x)}

Solution

y = - ln (e^{- x} - c_{1})

Solution steps

y^{'} (x) = e^{(y - x)}

Solve separable ODE:

y = - ln (e^{- x} - c_{1})

y = - ln (e^{- x} - c_{1})

Popular Examples

((q^4)/4+(2q^3)/3-(11q^2)/2+12q)^'

(\frac{q ^{4}}{4} + \frac{2 q ^{3}}{3} - \frac{11 q ^{2}}{2} + 12 q)^{^{'}}

4(1+x^2)(dy)/(dx)=2xy(y^4-1)

4 (1 + x^{2}) \frac{d y}{d x} = 2 x y (y^{4} - 1)

derivative of f(x)= 3/4 x derivative of

f (x) = \frac{3}{4} x

derivative of f(x)=(arctan(8x))^2 derivative of

f (x) = (arctan (8 x))^{2}

e^{5 y} y^{^{'}} = x^{3}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{(y-x)} ?
The solution for y^'=e^{(y-x)} is y=-ln(e^{-x}-c_{1})