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Popular >

area y=x^3,0<= x<= 5

Solution

area

y = x^{3}, 0 \leq x \leq 5

Solution

\frac{625}{4}

+1

Solution steps

Apply the area formula:

\int_{0}^{5} x^{3} d x

Solve

\int_{0}^{5} x^{3} d x : \frac{625}{4}

The area is:

= \frac{625}{4}

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inverse oflaplace s^2+4s+13 inverse laplace

s^{2} + 4 s + 13

(\partial)/(\partial z)(cos(z){w}(z))

\frac{\partial}{\partial z} (cos (z) w (z))

(dy)/(dt)=2(1-y),y(0)=0

\frac{d y}{d t} = 2 (1 - y), y (0) = 0

tangent of y=(8x)/(x^2+1),(0,0)tangent of

y = \frac{8 x}{x ^{2} + 1}, (0, 0)

Frequently Asked Questions (FAQ)

What is area y=x^3,0<= x<= 5 ?
The answer to area y=x^3,0<= x<= 5 is 625/4