What is the solution for x^2+3y(dy)/(dx)=0 ?

The solution for x^2+3y(dy)/(dx)=0 is y=(sqrt(-2x^3+c_{1)})/3 ,y=-(sqrt(-2x^3+c_{1)})/3

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x^2+3y(dy)/(dx)=0

x^{2} + 3 y \frac{d y}{d x} = 0

y = \frac{- 2 x ^{3} + c _{1}}{3}, y = - \frac{- 2 x ^{3} + c _{1}}{3}

Solution steps

x^{2} + 3 y \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{- 2 x ^{3} + c _{1}}{3}, y = - \frac{- 2 x ^{3} + c _{1}}{3}

y = \frac{- 2 x ^{3} + c _{1}}{3}, y = - \frac{- 2 x ^{3} + c _{1}}{3}

\int_{0}^{16} \frac{1}{x} d x

y^{^{'}} = ry

y^{^{''}} = - \frac{2}{t ^{2}}

y = x^{2} + 5 x + 9, at x = 4

\frac{\partial}{\partial x} (yz e^{x z} + e^{x z} + x y e^{x z})

What is the solution for x^2+3y(dy)/(dx)=0 ?
The solution for x^2+3y(dy)/(dx)=0 is y=(sqrt(-2x^3+c_{1)})/3 ,y=-(sqrt(-2x^3+c_{1)})/3