What is the derivative of 925+20x-0.079x^2 ?

The derivative of 925+20x-0.079x^2 is -0.158x+20

What is the first derivative of 925+20x-0.079x^2 ?

The first derivative of 925+20x-0.079x^2 is -0.158x+20

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derivative of

925 + 20 x - 0.079 x^{2}

- 0.158 x + 20

Solution steps

\frac{d}{d x} (925 + 20 x - 0.079 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (925) + \frac{d}{d x} (20 x) - \frac{d}{d x} (0.079 x^{2})

\frac{d}{d x} (925) = 0

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (0.079 x^{2}) = 0.158 x

= 0 + 20 - 0.158 x

Simplify

= - 0.158 x + 20

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What is the derivative of 925+20x-0.079x^2 ?
The derivative of 925+20x-0.079x^2 is -0.158x+20
What is the first derivative of 925+20x-0.079x^2 ?
The first derivative of 925+20x-0.079x^2 is -0.158x+20