What is (d^2)/(dx^2)(2sin(-4x-3)) ?

The answer to (d^2)/(dx^2)(2sin(-4x-3)) is 32sin(3+4x)

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(d^2)/(dx^2)(2sin(-4x-3))

\frac{d ^{2}}{d x ^{2}} (2 sin (- 4 x - 3))

32 sin (3 + 4 x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (2 sin (- 4 x - 3))

Simplify

2 sin (- 4 x - 3) : - 2 sin (3 + 4 x)

= \frac{d ^{2}}{d x ^{2}} (- 2 sin (3 + 4 x))

\frac{d}{d x} (- 2 sin (3 + 4 x)) = - 8 cos (3 + 4 x)

= \frac{d}{d x} (- 8 cos (3 + 4 x))

\frac{d}{d x} (- 8 cos (3 + 4 x)) = 32 sin (3 + 4 x)

= 32 sin (3 + 4 x)

n = 2 \sum \infty \frac{1}{5 ^{n}}

x \to 0 lim (\frac{sin ( x )}{8 x})

f (x) = \frac{sin ( x ) + cos ( x )}{e ^{x}}

\int 3 x^{2} - 8 x + C d x

h (x) = (x tan (x))^{7}

What is (d^2)/(dx^2)(2sin(-4x-3)) ?
The answer to (d^2)/(dx^2)(2sin(-4x-3)) is 32sin(3+4x)