What is the integral of 3x^2-8x+C ?

The integral of 3x^2-8x+C is x^3-4x^2+Cx+C

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integral of 3x^2-8x+C

\int 3 x^{2} - 8 x + C d x

x^{3} - 4 x^{2} + C x + C

Solution steps

\int 3 x^{2} - 8 x + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 8 x d x + \int C d x

\int 3 x^{2} d x = x^{3}

\int 8 x d x = 4 x^{2}

\int C d x = C x

= x^{3} - 4 x^{2} + C x

Add a constant to the solution

= x^{3} - 4 x^{2} + C x + C

h (x) = (x tan (x))^{7}

\int x sin (a x) d x

\int ln (cos (x)) d x

y^{^{'}} = 1 - \frac{y}{100}

sin (x)