What is the integral from 0 to 9 of 3/(\sqrt[3]{x-1)} ?

The integral from 0 to 9 of 3/(\sqrt[3]{x-1)} is 27/2

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integral from 0 to 9 of 3/(\sqrt[3]{x-1)}

\frac{27}{2}

Decimal Notation

13.5

Solution steps

Find undefined (singularity) points:

x = 1

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= - \frac{9 ( - 1 ) ^{\frac{2}{3}}}{2} + 18

Simplify

- \frac{9 ( - 1 ) ^{\frac{2}{3}}}{2} + 18 : \frac{27}{2}

= \frac{27}{2}

f (4) = 4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x

\frac{d ^{2}}{d x ^{2}} (sec (θ))

- \frac{1}{x ^{3}}

\int_{- \infty}^{0} e^{- 3 x} d x

x^{3} + 2 x + 1, 2

What is the integral from 0 to 9 of 3/(\sqrt[3]{x-1)} ?
The integral from 0 to 9 of 3/(\sqrt[3]{x-1)} is 27/2