What is the solution for (dy}{dx}=x+\frac{3y)/x ?

The solution for (dy}{dx}=x+\frac{3y)/x is y=-x^2+c_{1}x^3

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(dy}{dx}=x+\frac{3y)/x

\frac{d y}{d x} = x + \frac{3 y}{x}

y = - x^{2} + c_{1} x^{3}

Solution steps

\frac{d y}{d x} = x + \frac{3 y}{x}

Solve linear ODE:

y = - x^{2} + c_{1} x^{3}

y = - x^{2} + c_{1} x^{3}

\frac{\partial}{\partial x} (\frac{1}{y} - \frac{1}{x ^{2}})

\frac{\partial}{\partial y} (5 x^{2} y^{2})

x d y - (2 x e^{\frac{- y}{x}} + y) d x = 0

\frac{d}{d θ} (8 cos (θ) + 2 sin (θ))

\frac{d y}{d x} - x e^{y} = 2 e^{y}

What is the solution for (dy}{dx}=x+\frac{3y)/x ?
The solution for (dy}{dx}=x+\frac{3y)/x is y=-x^2+c_{1}x^3