What is the solution for y^'-y/x =tan(y/x) ?

The solution for y^'-y/x =tan(y/x) is y=arcsin(c_{1}x)x+2pinx,y=pix+arcsin(-c_{1}x)x+2pinx

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y^'-y/x =tan(y/x)

y^{^{'}} - \frac{y}{x} = tan (\frac{y}{x})

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

Solution steps

y^{'} (x) - \frac{y}{x} = tan (\frac{y}{x})

Solve using substitution:

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

y = arcsin (c_{1} x) x + 2 πn x, y = π x + arcsin (- c_{1} x) x + 2 πn x

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\frac{d y}{d x} = \frac{( x - 4 )}{( y + 5 )}

a x^{2} + b x + c

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\int_{0}^{\frac{π}{4}} 6 sec^{2} (x) d x

What is the solution for y^'-y/x =tan(y/x) ?
The solution for y^'-y/x =tan(y/x) is y=arcsin(c_{1}x)x+2pinx,y=pix+arcsin(-c_{1}x)x+2pinx