What is the derivative of f(x)=-4x^2-3x ?

The derivative of f(x)=-4x^2-3x is -8x-3

What is the first derivative of f(x)=-4x^2-3x ?

The first derivative of f(x)=-4x^2-3x is -8x-3

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derivative of

f (x) = - 4 x^{2} - 3 x

- 8 x - 3

Solution steps

\frac{d}{d x} (- 4 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= - 8 x - 3

\frac{\partial}{\partial x} (x^{2} + y^{2} + 1)

f (x) = \frac{x}{( x - 7 ) ^{2}}

\frac{( e ^{x} + e ^{- x} )}{2}

x \to 0 lim (\frac{x}{x + ∣ x ∣})

y = \frac{1}{18 x ^{2}}, y = x, y = \frac{x}{10}

What is the derivative of f(x)=-4x^2-3x ?
The derivative of f(x)=-4x^2-3x is -8x-3
What is the first derivative of f(x)=-4x^2-3x ?
The first derivative of f(x)=-4x^2-3x is -8x-3