What is the tangent of f(x)=x^2+6 ?

The tangent of f(x)=x^2+6 is y=2a_{0}x-a_{0}^2+6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+6

tangent of

f (x) = x^{2} + 6

y = 2 a_{0} x - a_{0}^{2} + 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + 6)

Find the slope of

f (x) = x^{2} + 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 6

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} + 6) : y = 2 a_{0} x - a_{0}^{2} + 6

y = 2 a_{0} x - a_{0}^{2} + 6

\int_{0}^{1} 36 π (x^{2} - x^{10}) d x

x \to 0 lim (1 - x)

\int \frac{9}{35 sin ( x ) - 12 cos ( x )} d x

\int (x + 1) (x^{2} + 2 x + 5)^{12} d x

\frac{d}{d x} (3 x^{2} - 24 x + 45)

What is the tangent of f(x)=x^2+6 ?
The tangent of f(x)=x^2+6 is y=2a_{0}x-a_{0}^2+6