What is (\partial)/(\partial x)(((x+y))/((x-y)^2)) ?

The answer to (\partial)/(\partial x)(((x+y))/((x-y)^2)) is (-x-3y)/((x-y)^3)

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(\partial)/(\partial x)(((x+y))/((x-y)^2))

\frac{\partial}{\partial x} (\frac{( x + y )}{( x - y ) ^{2}})

\frac{- x - 3 y}{( x - y ) ^{3}}

Solution steps

\frac{\partial}{\partial x} (\frac{( x + y )}{( x - y ) ^{2}})

Treat

y

as a constant

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial x} ( x + y ) ( x - y ) ^{2} - \frac{\partial}{\partial x} ( ( x - y ) ^{2} ) ( x + y )}{( ( x - y ) ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x + y) = 1

\frac{\partial}{\partial x} ((x - y)^{2}) = 2 (x - y)

= \frac{1 \cdot ( x - y ) ^{2} - 2 ( x - y ) ( x + y )}{( ( x - y ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x - y ) ^{2} - 2 ( x - y ) ( x + y )}{( ( x - y ) ^{2} ) ^{2}} : \frac{- x - 3 y}{( x - y ) ^{3}}

= \frac{- x - 3 y}{( x - y ) ^{3}}

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\frac{d}{d x} (\frac{2 x}{x ^{2} + 9})

\int_{0}^{1} x sin (\frac{nπ x}{2}) d x

What is (\partial)/(\partial x)(((x+y))/((x-y)^2)) ?
The answer to (\partial)/(\partial x)(((x+y))/((x-y)^2)) is (-x-3y)/((x-y)^3)