What is the tangent of f(x)= 2/x ,(-4,-1/2) ?

The tangent of f(x)= 2/x ,(-4,-1/2) is y=-1/8 x-1

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tangent of f(x)= 2/x ,(-4,-1/2)

tangent of

f (x) = \frac{2}{x}, (- 4, - \frac{1}{2})

y = - \frac{1}{8} x - 1

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(- 4, - \frac{1}{2}) : m = - \frac{1}{8}

Find the line with slope m=

- \frac{1}{8}

and passing through

(- 4, - \frac{1}{2}) : y = - \frac{1}{8} x - 1

y = - \frac{1}{8} x - 1

\frac{d}{d x} (x^{2} (x + 3)^{4})

n = 1 \sum \infty \frac{5 ^{n}}{6 ^{n} n}

x y^{^{'}} + y = 3 x y

\int (x^{2} + 7 x - 3) sin (2 x) d x

\int \frac{3}{x ( x ^{2} + 1 )} d x

What is the tangent of f(x)= 2/x ,(-4,-1/2) ?
The tangent of f(x)= 2/x ,(-4,-1/2) is y=-1/8 x-1