What is laplacetransform-5cos(3t) ?

The answer to laplacetransform-5cos(3t) is -(5s)/(s^2+9)

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laplacetransform-5cos(3t)

laplace transform

- 5 cos (3 t)

- \frac{5 s}{s ^{2} + 9}

Solution steps

L {- 5 cos (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {cos (3 t)}

L {cos (3 t)} : \frac{s}{s ^{2} + 9}

= - 5 \cdot \frac{s}{s ^{2} + 9}

Refine

- 5 \frac{s}{s ^{2} + 9} : - \frac{5 s}{s ^{2} + 9}

= - \frac{5 s}{s ^{2} + 9}

f (t) = 2 t^{3} + t

\frac{\partial}{\partial x} (\frac{x y}{x + y})

f (x) = ln (6 - x^{2})

\frac{\partial}{\partial x} (x cos (y) - y sin (x))

y = \frac{2 x}{x ^{2} + 1}, (- 1, - 1)

What is laplacetransform-5cos(3t) ?
The answer to laplacetransform-5cos(3t) is -(5s)/(s^2+9)