What is laplacetransform {cos(t)} ?

The answer to laplacetransform {cos(t)} is s/(s^2+1)

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laplacetransform {cos(t)}

laplace transform

{cos (t)}

\frac{s}{s ^{2} + 1}

Solution steps

L {cos (t)}

Use Laplace Transform table:

L {cos (a t)} = \frac{s}{s ^{2} + a ^{2}}

L {cos (t)} = \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1 ^{2}}

= \frac{s}{s ^{2} + 1}

f (t) = cos (8 t)

f (x) = x^{3} - 3 x + 4

y^{^{''}} + 6 y^{^{'}} + 5 y = 2 x

f (x) = 3 x^{\frac{1}{2}} + x^{\frac{3}{2}}, at x = 16

\int \frac{2}{x ( ln ( x ) ) ^{2}} d x

What is laplacetransform {cos(t)} ?
The answer to laplacetransform {cos(t)} is s/(s^2+1)