What is (\partial)/(\partial y)(x^2-y) ?

The answer to (\partial)/(\partial y)(x^2-y) is -1

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(\partial)/(\partial y)(x^2-y)

\frac{\partial}{\partial y} (x^{2} - y)

- 1

Solution steps

\frac{\partial}{\partial y} (x^{2} - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0

\frac{\partial}{\partial y} (2 x y + z^{2})

\frac{\partial}{\partial x} (3 x ln (y) + y ln (z) - 2 x)

\int x (x + \frac{1}{x}) d x

\int x^{2} d x

What is (\partial)/(\partial y)(x^2-y) ?
The answer to (\partial)/(\partial y)(x^2-y) is -1